Solveeit Logo

Question

Physics Question on work, energy and power

A mass attached to one end of a string crosses top-most point on a vertical circle with critical speed. Its centripetal acceleration when string becomes horizontal will be (g = gravitational acceleration)

A

gg

B

3g3\,g

C

4g4\,g

D

6g6\,g

Answer

3g3\,g

Explanation

Solution

We know that,
velocity of particle at top-most point on vertical circle,
(vtop )=3rg...(i)\left(v_{\text {top }}\right)=\sqrt{3 r g} \,\,\,\, \,\, ...(i)
But centripetal acceleration (ac)=v2r\left(a_{c}\right)=\frac{v^{2}}{r}
ac=(3rg)2r\therefore \,\,\,\,\,\, a_{c} =\frac{(\sqrt{3 r g})^{2}}{r} \,\,\,\,\,\,\,\, [from E (i)]
ac=3rgra_{c} =\frac{3 r g}{r}
ac=3ga_{c} =3\, g