Question

A mass attached to a string of length L is revolved in a vertical circle with least velocity. The string breaks when the mass reaches at the highest point. The mass describes a parabolic path, then range of body w.r.t. the lowest point is

• A. L²
• B. L
• C. 2L
• D. $\sqrt{2}$L

Answer 1

Answer: (C)

2L

Answer 2

Velocity at the highest point,

v_h = $\sqrt{gL}$

Height of the mass = 2L

Time taken to fall = $\sqrt{\frac{2 \times 2L}{g}} = \sqrt{\frac{4L}{g}}$

Horizontal distance covered

= v_ht = $\sqrt{gL} \times \sqrt{\frac{4L}{g}}$ = 2L