Question

A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10s. Then the coefficient of friction is –

• A. 0.01
• B. 0.02
• C. 0.03
• D. 0.06

Answer 1

Answer: (D)

0.06

Answer 2

v² = u² + 2as

0 = u² + (–2µg) s Ž µ = $\frac{u^{2}}{2gs}$