Question

A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10s. Then the coefficient of friction is

• A. 0.01
• B. 0.02
• C. 0.03
• D. 0.06

Answer 1

Answer: (D)

0.06

Answer 2

$v = u - at$ $= u - \mu gt = 0$

∴ $\mu = \frac{u}{gt} = \frac{6}{10 \times 10} = 0.06$.