Question

A marble block of mass $2 \,kg$ lying on ice when given a velocity of $6\, m/s$ is stopped by friction in $10\, s$. then the coefficient of friction is

• A. $0.02$
• B. $0.03$
• C. $0.06$
• D. $0.04$

Answer 1

Answer: (C)

$0.06$

Answer 2

Retardation $\frac{u}{t}=\frac{6}{10}=0.6\,m/sec^{2}$ Frictional force $= ?\, mg = ma$ $\therefore \mu=\frac{a}{g}=\frac{0.6}{10}=0.06.$