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Question

Mathematics Question on Linear Programming Problem

A manufacturer makes two types of toys A and B. Three machines are needed for this purpose and the time(in minutes)required for each toy on the machines is given below:
A manufacturer makes two types of toys
Each machine is available for a maximum 6 hours per day.If the profit on each toy of type A is Rs7.50 and that on each toy of type B is Rs5, show that 15 toys of type A and 30 toys of type B should be manufactured in a day to get maximum profit.

Answer

Let X and Y toys of type A and type B respectively manufactured in a day.

The given problem can be formulated as follows.

Maximize Z=7.5x+5y..(1)

Subject to the constraints,
2x+y≤60...(2)
x≤20...(3)
2x+3y≤120....(4)
x,y≥0...(5)

The feasible region determined by the constraints is as follows.

feasible region determined by the constraints

The corner points of the feasible region are A(20,0), B(20,20), C(15,30) and D(0,40).

The value of Z at these corner points is as follows.

Corner point| Z=7.5x+5y|
---|---|---
A(20,0)| 150|
B(20,20)| 250|
C(15,30)| 262.5| \rightarrowMaximum
O(40,0)| 200|

Thus, the manufacturer should manufacture 15 toys of type A and 30 types of toy B to maximize the profit.