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Question: A man with defective eyes cannot see distinctly object at the distance more than 60 cm from his eyes...

A man with defective eyes cannot see distinctly object at the distance more than 60 cm from his eyes. The power of the lens to be used will be

A
  • 60 D
B

– 60 D

C

– 1.66 D

D

11.66D\frac { 1 } { 1.66 } D

Answer

– 1.66 D

Explanation

Solution

f=−d=−60 cmf = - d = - 60 \mathrm {~cm}

∴P=100f=−10060=−106=−1.66D\therefore P = \frac { 100 } { f } = - \frac { 100 } { 60 } = - \frac { 10 } { 6 } = - 1.66 \mathrm { D }