Question
Physics Question on laws of motion
A man weighing 60 kg is in a lift moving down with an acceleration of 1.8ms−2. The force exerted by the floor on him is
A
588 N
B
480 N
C
Zero
D
696 N
Answer
480 N
Explanation
Solution
R=m(g−a)=60(9.8−1.8)
=480N