Solveeit Logo

Question

Physics Question on laws of motion

A man weighing 60 kg is in a lift moving down with an acceleration of 1.8ms21.8 \, ms^{-2}. The force exerted by the floor on him is

A

588 N

B

480 N

C

Zero

D

696 N

Answer

480 N

Explanation

Solution

R=m(ga)=60(9.81.8)R = m(g - a)= 60(9.8 - 1.8)
=480N= 480\, N