Question

A man weighing $60\, kg$ is in a lift moving down with an acceleration of $1.8\, m/s^2$. The floor exerts on him a force equal to :

• A. 696 N
• B. zero
• C. 480 N
• D. 588 N

Answer 1

Answer: (C)

480 N

Answer 2

Here: $m=60\, kg,\, a=1.8\, m / s ^{2},$ $g=9.8\, m / s ^{2}$ Apparent weight of man $\omega=m g-m a$ or $\omega=60(9.8-1.8)=480\, N$