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Question: A man throws a ball vertically upward and it rises through 20 m and returns to his hands. What was t...

A man throws a ball vertically upward and it rises through 20 m and returns to his hands. What was the initiasl velocity (u)(u) of the ball and for how much time (T)(T) it remained in the air [g=10m/s2]\lbrack g = 10m/s^{2}\rbrack

A

u = 10 m/s, T = 2s

B

u = 10 m/s, T = 4s

C

u = 20 m/s, T = 2s

D

u = 20 m/s, T = 4s

Answer

u = 20 m/s, T = 4s

Explanation

Solution

u=2gh=2×10×20=206mum/su = \sqrt{2gh} = \sqrt{2 \times 10 \times 20} = 20\mspace{6mu} m/s

and T=2ug=2×2010=4T = \frac{2u}{g} = \frac{2 \times 20}{10} = 4sec