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Question: A man takes a step forward with probability 0.4 and backward with probability 0.6. The probability t...

A man takes a step forward with probability 0.4 and backward with probability 0.6. The probability that at the end of eleven steps he is one step away from the starting point is

A

11C6(0.24)5{ } ^ { 11 } C _ { 6 } ( 0.24 ) ^ { 5 }

B

11C6(0.4)6(0.6)5{ } ^ { 11 } C _ { 6 } ( 0.4 ) ^ { 6 } ( 0.6 ) ^ { 5 }

C

11C6(0.6)6(0.4)5{ } ^ { 11 } C _ { 6 } ( 0.6 ) ^ { 6 } ( 0.4 ) ^ { 5 }

D

None of these

Answer

11C6(0.24)5{ } ^ { 11 } C _ { 6 } ( 0.24 ) ^ { 5 }

Explanation

Solution

The man will be one step away from the starting point if (i) either he is one step ahead or (ii) one step behind the starting point.

∴ The required probability = P(i) + P(ii)

The man will be one step ahead at the end of eleven steps if he moves six step forward and five steps backward.

The probability of this event is 11C6(0.4)6(0.6)5{ } ^ { 11 } C _ { 6 } ( 0.4 ) ^ { 6 } ( 0.6 ) ^ { 5 }.

The man will be one step behind at the end of eleven steps if he moves six steps backward and five steps forward.

The probability of this event is 11C6(0.6)6(0.4)5{ } ^ { 11 } C _ { 6 } ( 0.6 ) ^ { 6 } ( 0.4 ) ^ { 5 }.

Hence the required probability

.