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Question

Physics Question on Electromagnetic waves

A man stands in a narrow, steep-sided valley. When he shouts he hears two echoes, one after l s and other after 2 s. If the velocity of sound in air is 330 m/s, the width of the valley is

A

330 m

B

495 m

C

660 m

D

990 m

Answer

495 m

Explanation

Solution

Let s1s_1 and s2s_2 be the distances of man from either side of valley,
then

\hspace35mm 2s_1 =vt_1 and 2s2=vt22s_2 = vt_2
\Rightarrow \hspace15mm 2(s_1 + s_2)=v(t_1 + t_2)
\Rightarrow \hspace20mm s_1 + s_2= \frac{v(t_1 + t_2)}{2}
\therefore \hspace25mm d = s_1 + s_2
\hspace32mm = \frac{330 \times (1+2)}{2}
\Rightarrow \hspace25mm d = \frac{330 \times 3}{2} = 495\, m