Question
Physics Question on Electromagnetic waves
A man stands in a narrow, steep-sided valley. When he shouts he hears two echoes, one after l s and other after 2 s. If the velocity of sound in air is 330 m/s, the width of the valley is
A
330 m
B
495 m
C
660 m
D
990 m
Answer
495 m
Explanation
Solution
Let s1 and s2 be the distances of man from either side of valley,
then
\hspace35mm 2s_1 =vt_1 and 2s2=vt2
\Rightarrow \hspace15mm 2(s_1 + s_2)=v(t_1 + t_2)
\Rightarrow \hspace20mm s_1 + s_2= \frac{v(t_1 + t_2)}{2}
\therefore \hspace25mm d = s_1 + s_2
\hspace32mm = \frac{330 \times (1+2)}{2}
\Rightarrow \hspace25mm d = \frac{330 \times 3}{2} = 495\, m