Question

A man slides down a light rope whose breaking strength is $\eta$ times his weight. What should be his maximum acceleration so that the rope just not breaks?

• A. $g(1-\eta )$
• B. $\eta g$
• C. $\frac{g}{1+\eta }$
• D. $\frac{g}{1-\eta }$

Answer 1

Answer: (A)

$g(1-\eta )$

Answer 2

$mg-R=ma$ $mg=\eta mg=ma$ $[\because \,R=\eta \,mg]$ $mg(1-\eta )=ma$ $a=g(1-\eta )$