Question
Question: A man on the top of a cliff 100 m high, observe the angles of depression of two points on the opposi...
A man on the top of a cliff 100 m high, observe the angles of depression of two points on the opposite sides of the cliff as 30∘ and 60∘ respectively. Then, the distance between the two points is equal to
(a)4003m
(b)3400m
(c)3100m
(d)2003
Solution
Hint: For solving this problem, we consider two triangles ABD and ADC having respective bases as a and b in metres. Now, by applying the trigonometric ratio of tanθ in both the triangles, we obtain the respective bases individually as height is already given in the problem statement. By adding both the bases of the triangle, we get the final answer.
Complete step-by-step answer:
Let, the base of triangle ABD be ‘a’ meters and base of triangle ADC be ‘b’ meters.
According to the problem statement, the height of the cliff is 100m, ∠ABD=60∘ and ∠ACD=30∘.
One useful trigonometric ratio involved in this problem is tan which can be expressed as:
tanθ=baseperpendicular
In ΔABD, applying tan60∘, we get
tan60∘=BDAD
As we know that the value of tan60∘=3, AD =100m and BD = a meter. Therefore, to evaluate a we put the values in the above ratio.
3=a100a=3100m
The length of BD is 3100m.
In ΔADC, applying tan30∘, we get
tan30∘=DCAD
As we know that the value of tan30∘=31, AD = 100 m and DC = b meter.
31=b100b=1003m
The value of DC is 1003m,
Adding both the value of BD and DC with each other, we get
a+b=3100+1003a+b=3400m
Hence, the distance between two points is 3400m.
Therefore, option (b) is correct.
Note: The key concept involved in solving this problem is the knowledge of trigonometric ratio in the form of triangles. Once we know the value of angle subtended, we can easily find the ratio between the length by using tan operation.