Question
Physics Question on laws of motion
A man of mass 60 kg is riding in a lift. The weight of the man, when the lift is accelerating upwards and downwards at 2 ms−2, are respectively . (Taking g = 10 ms−2)
A
720 N and 480 N
B
480 N and 720 N
C
600 N and 600 N
D
None of the above
Answer
720 N and 480 N
Explanation
Solution
When the lift is accelerating upwards with a constant acceleration a, then weight, w = m(g + a) =60(10+2)=60×12 =720N When the lift is accelerating downwards at the rate a, then weight, w' = m(g - a) =60(10−2)=60×8 =480N