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Question

Physics Question on laws of motion

A man of mass 60 kg is riding in a lift. The weight of the man, when the lift is accelerating upwards and downwards at 2 ms2ms^{-2}, are respectively . (Taking g = 10 ms2)ms^{-2})

A

720 N and 480 N

B

480 N and 720 N

C

600 N and 600 N

D

None of the above

Answer

720 N and 480 N

Explanation

Solution

When the lift is accelerating upwards with a constant acceleration a, then weight, w = m(g + a) =60(10+2)=60×12 \, \, \, \, \, \, \, = 60 (10+2) = 60 \times 12 =720N \, \, \, \, \, \, \, \, = 720N When the lift is accelerating downwards at the rate a, then weight, w' = m(g - a) =60(102)=60×8 \, \, \, \, \, \, \, \, =60(10-2)=60 \times 8 =480N \, \, \, \, \, \, \, \, =480N