Question

A man of mass $60 \,kg$ climbed down using an elevator. The elevator had an acceleration $4 \, ms^{-2}$. If the acceleration due to gravity is $10 \, ms^{-2}$, the main apparent weight on his way down is

• A. 60 N
• B. 240 N
• C. 360 N
• D. 840 N

Answer 1

Answer: (C)

360 N

Answer 2

The man is climbing down using elevator, so the resultant gravity on the man will be
$\because g^{'}=g-a=10-4$
$=6\, m / s ^{2}$
The weight of the person, $W=m g^{'}$
$=60 \times 6=360 \,N$