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Question: A man of mass 50 kg is moving up an inclined plane pull a block of mass 25 kg with constant speed 1 ...

A man of mass 50 kg is moving up an inclined plane pull a block of mass 25 kg with constant speed 1 m/s. Friction coefficient between block and plane is 0.5. Assuming that man doesn’t slips. Power delivered by man –

A

0.65 kW

B

0.75 kW

C

0.25 kW

D

0.45 kW

Answer

0.65 kW

Explanation

Solution

Sol. For mass and block system –

Pm + Pf + Pmg = 0 \ Dk = 0

\ Pm = – (Pf + Pmg)

−{(−μmg.45.v)+(−(m+M)g.35.v)}- \left\{ \left( - \mu mg.\frac{4}{5}.v \right) + \left( - (m + M)g.\frac{3}{5}.v \right) \right\}

[m = mass of block,

M = mass of man]

= 0.65 kW