Question

A man moves in an open field such that after moving 10 m in a straight line, he makes a sharp turn of 60° to his left. The total displacement of the man just after 7 such turns is

Answer 1

10 m

Answer 2

1. The man walks 10 m and then turns 60° to the left. Repeating this, note that after 6 moves the turns add up to 6×60° = 360° so that the 6 segments form a closed regular hexagon (net displacement zero).

2. Therefore, after 6 moves the man is at his starting point. After the next (7th) move of 10 m the net displacement is simply that extra 10 m.

Thus, the total displacement just after 7 such turns is 10 m.

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Minimal Explanation:

A regular hexagon is completed in 6 moves (since 6×60° = 360°). Hence, after 6 moves the displacement is zero; the 7th move adds 10 m.