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Question: A man is running towards a plane mirror at a speed of \(2m{s^{ - 1}}\). How fast does he see himself...

A man is running towards a plane mirror at a speed of 2ms12m{s^{ - 1}}. How fast does he see himself running towards his image?
A.2m/s
B.4m/s
C.5m/s
D.3m/s

Explanation

Solution

Here in this question we have to keep in mind that the person who is standing in front of the mirror seeing his image is approaching his image at 2ms12m{s^{ - 1}}. As he is approaching his image, the image is also approaching him at the same speed, so the two speeds will be added.

Complete answer:
Here the person will cover the given amount of distance in the required amount of time at the rate of 2ms12m{s^{ - 1}}. In reality the person would have the same speed of 2ms12m{s^{ - 1}} but he would see himself running towards his image at 4ms14m{s^{ - 1}}. This is so because the image is also running towards him at the speed of 2ms12m{s^{ - 1}} so, both of the velocities would add up (2ms12m{s^{ - 1}} of the person running towards his image +2ms12m{s^{ - 1}} of the image running towards the person =4ms14m{s^{ - 1}}). It is an illusion that the person sees himself running towards his image. In actuality the person is running at his original speed of 2ms12m{s^{ - 1}}. The man is running towards a plane mirror at a speed of 2ms12m{s^{ - 1}}. Sees himself running towards his image at the speed of 4ms14m{s^{ - 1}}.

So, Option (B) is the correct answer:

Note:
Here, one can be easily mistaken and give the answer 2ms12m{s^{ - 1}} which is the person’s real speed/velocity. One has to read the question carefully to know that in the question it is asked the total speed at which the person sees himself running towards his image.