Question
Question: A magnetic needle of magnetic moment and moment of inertia is performing simple harmonic oscillation...
A magnetic needle of magnetic moment and moment of inertia is performing simple harmonic oscillations in a magnetic field of 0.01 T. Time taken for 10 complete oscillations is:
A. 8.76 s
B. 6.65 s
C. 8.89 s
D. 6.98 s
Solution
By using the equation for time period, we can solve this question.
T=2πMBI
Where I is the moment of inertia, M is the magnetic moment and B is the magnetic field.
Complete answer:
In the question, it is given that
Magnetic moment is
M=6.7×10−2 Am2
Moment of inertia is
I=7.5×10−6kgm2
Magnetic field is
B=0.01T
We know that time period of oscillation is given by the formula
T=2πMBI
Applying the values given in the question to the equation gives,
T=2π×6.7×10−2×0.017.5×10−6
Performing the operations gives,
T=2π×0.1058T=0.66477
Therefore we will get like,
T=0.6647s
We know Time period is known as the time required to complete one oscillation.
Therefore, to complete ten oscillations
t=10×Tt=10×0.66477t=6.6477
Therefore
t≈6.65s
So the correct answer is option B.
Additional Information:
Magnetic moment is the product of the pole distances with the strength of the magnetic pole. It is a vector quantity. Moment of inertia is the quantity which shows the reluctance of an object to acquire angular acceleration. In simple words it is the ratio of angular momentum of a body to the angular velocity around the principal axis of the body. Magnetic field is the tendency of attraction or influence on an electronic charge.
Note:
There is a chance of getting confused with the two options B and D as they are almost similar values.so be careful in using the decimal digits during operations like multiplication, division etc. Here the answer for this question is t≈6.65s.