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Question: A magnetic dipole in a constant magnetic field has: (A) Minimum potential energy when the torque i...

A magnetic dipole in a constant magnetic field has:
(A) Minimum potential energy when the torque is maximum.
(B) Zero potential energy when the torque is minimum.
(C) Zero potential energy when the torque is maximum.
(D) Maximum potential energy when the torque is maximum.

Explanation

Solution

We are given the magnetic dipole in a constant magnetic field and are asked about the change in torque when there is a change in potential energy. Thus, we will take a formula of potential energy and then discuss the change in it. Then, we will take a formula for torque on a magnetic dipole. Then finally we will try to connect the change in both these parameters.
Formula Used
U=μ.B=μBcosθU = - \vec \mu .\vec B = - \mu B\cos \theta
Where, UU is the potential energy on a magnetic dipole, μ\vec \mu is the magnetic dipole moment of the dipole and B\vec B is the uniform magnetic field in which the magnetic dipole is placed and θ\theta is the angle between μ\mu and BB .
τ=μ×B=μBsinθn^\vec \tau = \vec \mu \times \vec B = \mu B\sin \theta \hat n
Where, τ\vec \tau is the torque acting on the magnetic dipole, μ\vec \mu is the magnetic dipole moment of the dipole and B\vec B is the uniform magnetic field in which the magnetic dipole is placed and θ\theta is the angle between μ\mu and BB . n^\hat n is the direction of the torque which is perpendicular to the plane containing μ\vec \mu and B\vec B .

Step By Step Solution
We know,
Potential energy of the magnetic dipole, U=μ.B=μBcosθU = - \vec \mu .\vec B = - \mu B\cos \theta
Now,
The magnetic dipole moment (μ\vec \mu ) and magnetic field (B\vec B) are constant parameters, only the cosθ\cos \theta is the only varying parameter.
Now,
cosθ\cos \theta is maximum when cosθ=1\cos \theta = 1 or θ=2nπ;n=0,1,2,...\theta = 2n\pi ;n = 0,1,2,... and then cosθ\cos \theta is minimum when cosθ=1\cos \theta = - 1 or θ=(2n1)π;n=0,1,2,3,...\theta = (2n - 1)\pi ;n = 0,1,2,3,....
Also,
We know,
Torque acting on the magnetic dipole, τ=μ×B=μBsinθn^\vec \tau = \vec \mu \times \vec B = \mu B\sin \theta \hat n
From this, we will only take the magnitude of the torque in order to compare the change with the potential energy change.
Thus,
τ=μBsinθ|\vec \tau | = \mu B\sin \theta
Out of here also only the sinθ\sin \theta is the varying parameter.
Now,
sinθ\sin \theta is maximum when sinθ=1\sin \theta = 1 or θ=(2n+1)π2;n=1,2,3,...\theta = (2n + 1)\dfrac{\pi }{2};n = 1,2,3,... and sinθ\sin \theta is minimum when sinθ=0\sin \theta = 0 or θ=nπ;n=0,1,2,...\theta = n\pi ;n = 0,1,2,....
Thus, we can say that the points when the value of cosθ\cos \theta is maximum when sinθ\sin \theta is minimum and vice versa. Broadly speaking, when potential energy is zero, then the torque is maximum.

Hence, the answer is (C).

Note: We were asked to find the relation between potential energy and torque of the magnetic dipole. If we were asked for the relation between some other parameters, the calculations would be somewhat different but the workflow remains the same.