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Question: A magnet of length 0.1 m and pole strength \(\times 10 ^ { - 4 } \mathrm { Nm }\)...

A magnet of length 0.1 m and pole strength ×10−4Nm\times 10 ^ { - 4 } \mathrm { Nm }

A

7.5

B

3.0

C

1.5

D

6.0

Answer

1.5

Explanation

Solution

τ=MBsin⁡θ=m×(2l)×Bsin⁡θ\tau = M B \sin \theta = m \times ( 2 l ) \times B \sin \theta

=10−4×0.1×30sin⁡30∘= 10 ^ { - 4 } \times 0.1 \times 30 \sin 30 ^ { \circ } =1.5×10−4Nm= 1.5 \times 10 ^ { - 4 } \mathrm { Nm }