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Question: A machine gun is mounted on a 2000 kg car on a horizontal frictionless surface. At some instant the ...

A machine gun is mounted on a 2000 kg car on a horizontal frictionless surface. At some instant the gun fires bullets of mass 10 gm with a velocity of 500 m/sec with respect to the car. The number of bullets fired per second is ten. The average thrust on the system is

A

550 N

B

50 N

C

250 N

D

250 dyne

Answer

50 N

Explanation

Solution

u = velocity of bullet

dmdt=\frac { d m } { d t } =Mass thrown per second by the machine gun

= Mass of bullet × Number of bullet fired per second

=100 g/sec=0.1 kg/sec= 100 \mathrm {~g} / \mathrm { sec } = 0.1 \mathrm {~kg} / \mathrm { sec }

\therefore Thrust =udmdt=500×0.1=50 N= \frac { u d m } { d t } = 500 \times 0.1 = 50 \mathrm {~N}