Question

A machine gun fires a bullet of mass 40 g with a velocity 1200 m s^–1 . The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?

• A. One
• B. Four
• C. Two
• D. Three

Answer 1

Answer: (D)

Three

Answer 2

F = mnv

144 = 40 × 10^–3 × n × 1200

n = $\frac{144}{4 \times 12}$ = 3