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Physics Question on Magnetic Field

A long wire carrying current (2)A\sqrt{(2)}A is placed in a uniform magnetic field of 3×10−5  T3 \times 10^{-5}\; T. If the magnetic field is perpendicular to wire, find magnetic force on the length of wire.

A

3×10−4  N3 \times 10^{-4}\; N

B

3(2)×10−5N3\sqrt{(2)} \times 10^{-5} N

C

3×10−3  N3 \times 10^{-3}\; N

D

Zero

Answer

3(2)×10−5N3\sqrt{(2)} \times 10^{-5} N

Explanation

Solution

The Correct Option is (B): 3(2)×10−5N3\sqrt{(2)} \times 10^{-5} N