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Question

Physics Question on Energy in simple harmonic motion

A long string is stretched by 2cm2\, cm and the potential energy is VV. If the spring is stretched by 10cm10\, cm, its potential energy will be

A

V/25

B

V/5

C

5 V

D

25 V

Answer

25 V

Explanation

Solution

V=12k(x)2=12k(2)2V=\frac{1}{2} k(x)^{2}=\frac{1}{2} k(2)^{2}
or k=2V4=V2k =\frac{2 V}{4}=\frac{V}{2}
V=12k(10)2=12×(V2)(10)2V'=\frac{1}{2} k(10)^{2}=\frac{1}{2} \times\left(\frac{V}{2}\right)(10)^{2}
=25V=25\, V