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Question

Physics Question on Moving charges and magnetism

A long straight wire of radius a'a' caries a steady current ii. The current across its cross section. The ratio of the magnetic field at a2\frac{a}{2} and 2a2a is

A

14\frac{1}{4}

B

44

C

11

D

12\frac{1}{2}

Answer

11

Explanation

Solution

B2πa2=μ0iπa2(πa24)B2\pi \frac{a}{2}=\mu_{0} \frac{i}{\pi a^{2}}\left(\frac{\pi a^{2}}{4}\right) B1=μ0i4πa...(i)B_{1}=\frac{\mu_{0}i}{4\,\pi a}\,...\left(i\right) B22π(2a)=μ0iB_{2}2\pi\left(2a\right)=\mu_{0}i B2=μ0i4πa...(ii)B_{2}=\frac{\mu_{0}i}{4\,\pi a}\,...\left(ii\right) B1B2=1\frac{B_{1}}{B_{2}}=1