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Question: A long straight wire carrying current of 30 A rests on a table. Another wire AB of length 1 m, mass ...

A long straight wire carrying current of 30 A rests on a table. Another wire AB of length 1 m, mass 3 g carries the same current but in the opposite direction, the wire AB is free to side up and down. The height upto which AB will rise is

A

0.6 cm

B

0.7 cm

C

0.4 cm

D

0.5 cm

Answer

0.6 cm

Explanation

Solution

Here

m=3 g=3×10−3kga\mathrm { m } = 3 \mathrm {~g} = 3 \times 10 ^ { - 3 } \mathrm { kga }

In equilibrium position

mg=μ04π2I1I2lh\mathrm { mg } = \frac { \mu _ { 0 } } { 4 \pi } \frac { 2 \mathrm { I } _ { 1 } \mathrm { I } _ { 2 } \mathrm { l } } { \mathrm { h } }

=0.6 cm=6×10−3 m= 0.6 \mathrm {~cm} = 6 \times 10 ^ { - 3 } \mathrm {~m}