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Question

Physics Question on Moving charges and magnetism

A long straight wire carries 10 Ad.cA \,d.c. current an electron travels perpendicular to the plane of this wire at a distance 0.1m0.1\, m with velocity 5.0×106ms15.0 \times10^6 m \,s^{-1}. Force acting on the electron due to current in wire is

A

zero N

B

0.6×1017N0.6 \times10^{-17} N

C

2.4×1017N2.4 \times10^{-17} N

D

2.2×1017N2.2 \times10^{-17} N

Answer

zero N

Explanation

Solution

Force on the electron F=e(v×B)\vec{F}=-e\left(\vec{v} \times\vec{B}\right). As electron is travelling in a plane perpendicular to the plane of wire, so angle ? between v\vec{v} and B\vec{B} is either 0^{\circ} or 180^{\circ} and sin 0^{\circ} or sin 180^{\circ} = 0.