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Physics Question on Moving charges and magnetism

A long solenoid of 50 cm50\,cm length having 100 turns100\,turns carries a current of 2.5 A2.5\,A. The magnetic field at the centre of the solenoid is : (μo=4π×10−7T m A−1)(\mu_o = 4\pi \times 10^{-7} T\,m\,A^{-1})

A

6.28×10−4T6.28 \times 10^{-4}T

B

3.14×10−4T3.14 \times 10^{-4}T

C

6.28×10−5T6.28 \times 10^{-5}T

D

3.14×10−5T3.14 \times 10^{-5}T

Answer

6.28×10−4T6.28 \times 10^{-4}T

Explanation

Solution

Magnetic field at centre of solenoid =μ0nI=\mu_{0}nI
n=NLn=\frac{N}{L}
=10050×10−2=\frac{100}{50 \times 10^{-2}}
=200=200 tums/m
I=2.5 AI = 2.5 \,A
On putting the values,
B=4π×10−7×200×2.5B=4\pi\times 10^{-7}\times 200 \times 2.5
=6.28×10−4 T=6.28 \times 10^{-4}\,T