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Question

Physics Question on Moving charges and magnetism

A long solenoid has 200200 turns per cm and carries a current ii. The magnetic field at its centre is 6.28×1026.28 \times 10^{-2} weber/m2m^2. Another long solenoid has 100 turns per cm and it carries a current i/3i/3. The value of the magnetic field at its centre is:

A

1.05×1021.05 \times 10^{-2} weber/m2m^2

B

1.05×1051.05 \times 10^{-5} weber/m2m^2

C

1.05×1031.05 \times 10^{-3} weber/m2m^2

D

1.05×1041.05 \times 10^{-4} weber/m2m^2

Answer

1.05×1021.05 \times 10^{-2} weber/m2m^2

Explanation

Solution

Magnetic field due to a long solenoid is given by B=μ0niB=\mu\,_{0}ni From given data, 6.28×102=μ0×200×102×i...(i)6.28\times10^{-2}=\mu_{0}\times 200\times10^{2}\times i ...\left(i\right) and B=μ0×100×102×(i/3)...(ii)B=\mu_{0} \times 100\times10^{2} \times\left(i/3\right)...\left(ii\right) Solving Eqs.(i) and (ii), we get B1.05×102Wb/m2B\approx1.05\times10^{-2}\,Wb/m^{2}