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Question

Physics Question on Electromagnetic induction

A long solenoid has 10001000 turns. When a current of 4A4\,A flows through it, the magnetic flux linked with each turn of the solenoid is 4×103Wb4 \times 10^{-3} \, Wb. The self-inductance of the solenoid is :

A

3 H

B

2 H

C

1 H

D

4 H

Answer

1 H

Explanation

Solution

Flux linked with each turn =4×103Wb= 4 \times 10^{-3} \, Wb
\therefore Total flux linked = 1000[4×103]Wb 1000[4 \times 10^{-3}] Wb
ϕtotal=4Li=4L=1H\phi_{total} = 4 \, \Rightarrow \, L \, i = 4 \, \Rightarrow \, L = 1 H