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Question: A locker can be opened by dialing a fixed three digit code (between 000 and 999). A stranger who doe...

A locker can be opened by dialing a fixed three digit code (between 000 and 999). A stranger who does not know the code tries to open the locker by dialing three digits at random. The probability that the stranger succeeds at the trial is

A

k999\frac { k } { 999 }

B

k1000\frac { k } { 1000 }

C

k11000\frac { k - 1 } { 1000 }

D

None of these

Answer

k1000\frac { k } { 1000 }

Explanation

Solution

Let AA denote the event that the stranger succeeds at the kthk ^ { t h } trial. Then

P(A)=9991000×998999×..×1000k+11000k+2×1000k1000k+1P \left( A ^ { \prime } \right) = \frac { 999 } { 1000 } \times \frac { 998 } { 999 } \times \ldots . . \times \frac { 1000 - k + 1 } { 1000 - k + 2 } \times \frac { 1000 - k } { 1000 - k + 1 }

\Rightarrow P(A)P \left( A ^ { \prime } \right) =1000k1000= \frac { 1000 - k } { 1000 }