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Question: A load W produces an extension of 1mm in a thread of radius r. Now if the load is made 4W and radius...

A load W produces an extension of 1mm in a thread of radius r. Now if the load is made 4W and radius is made 2r all other things remaining same, the extension will become

A

4 mm

B

16 mm

C

1 mm

D

0.25 mm

Answer

1 mm

Explanation

Solution

l=FLAYlFr2l = \frac { F L } { A Y } \therefore l \propto \frac { F } { r ^ { 2 } }

l1l2=F2F1(r1r2)2=(4)×(12)2=1\frac { l _ { 1 } } { l _ { 2 } } = \frac { F _ { 2 } } { F _ { 1 } } \left( \frac { r _ { 1 } } { r _ { 2 } } \right) ^ { 2 } = ( 4 ) \times \left( \frac { 1 } { 2 } \right) ^ { 2 } = 1l2=l1=1 mml _ { 2 } = l _ { 1 } = 1 \mathrm {~mm}