Question

A liquid of mass M and specific heat S is at a temperature 2t. If another liquid of thermal capacity 1.5 times, at a temperature of $\frac{t}{3}$ is added to it, the resultant temperature will be

• A. $\frac{4}{3}t$
• B. t
• C. $\frac{t}{2}$
• D. $\frac{2}{3}t$

Answer 1

Answer: (B)

t

Answer 2

$\theta_{mix} = \frac{m_{1}c_{1}\theta_{1} + m_{2}c_{2}\theta_{2}}{m_{1}c_{1} + m_{2}c_{2}} = \frac{ms(2t) + 1.5(ms) \times \frac{t}{3}}{ms + 1.5(ms)} = t$