Question

A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is

• A. (2/3)T
• B. (8/5)T
• C. (3/5)T
• D. (3/2)T

Answer 1

Answer: (D)

(3/2)T

Answer 2

Temperature of mixture is given by T = $\frac{m_{1}c_{1}T_{1} + m_{2}c_{2}T_{2}}{m_{1}c_{1} + m_{2}c_{2}} = \frac{m.c.2T + \frac{m}{2}.2.c.T}{m.c. + \frac{m}{2}.2c} = \frac{3}{2}T$