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Question: A liquid of cubical expansivity Y is heated in a vessel having linear expansivity \(\frac{Y}{3}\). T...

A liquid of cubical expansivity Y is heated in a vessel having linear expansivity Y3\frac{Y}{3}. Then level of liquid –

A

(a) Increase

A

(b) Decrease

A

(c) Remain same

A

(d) All-possible

Explanation

Solution

(c)

ys = 3 as

as = y3\frac{y}{3} given

So ys = 3 × y3\frac{y}{3} = y