Question
Question: A liquid of coefficient of the viscosity \(\eta = 1\) poise in a pipe of the radius \(3cm\) such tha...
A liquid of coefficient of the viscosity η=1 poise in a pipe of the radius 3cm such that the rate of volume flow is 1000l/min. Determine the Reynolds numbers.
(A)3563
(B)3500
(C)3400
(D)3600
Solution
The ratio of the inertial forces to the viscosity force that is subjected to the internal movement which is related to the different fluid velocities is known as the Reynolds number. It is a dimensionless number that is used to determine the types of flow patterns which are laminar or turbulent.
Formula used:
To find the Reynolds number,
Re=μρvL
Where,
ρ is the density,
v is the speed of the flow,
L is the linear dimension characteristic,
μis the dynamic viscosity
Complete step by step answer:
The values are given in the question. The liquid of coefficient of the viscosity η=1 poise, pipe of the radius 3cm, and the rate of volume flow are 1000l/min.
The rate of the flow is 1000l/min
The value of πr2is 601m3/s
Substitute all the values in the Reynolds formula. We have,
Re=μρvL
Where,
ρ is the density,
v is the speed of the flow,
L is the linear dimension characteristic,
μ is the dynamic viscosity
⇒Re=0.11000×60πr21×2r
⇒Re=0.11000×60πr22r
⇒Re=0.11000×60πr2
⇒Re=1.0×60π×r2000
The value of the radius is 3cm converting the centimeter into the meter we get,
⇒Re=1.0×60π×3×10−22000
Substituting the value of π,
⇒Re=1.0×60(3.16)×3×10−22000
⇒Re=568.8×10−22000
⇒Re=3563
Therefore the Reynolds number is 3563.
Hence option (A) is the correct answer
Note: If the Reynolds number has a high value the pipe has a turbulent flow. If the Reynolds number has a low value the pipe has a laminar flow. Numerically these values are acceptable though in general the laminar and turbulent flow can be classified according to the range.