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Question

Question: A liquid is filled into a tube with semi-elliptical cross-section as shown in the figure. The ratio ...

A liquid is filled into a tube with semi-elliptical cross-section as shown in the figure. The ratio of the surface tension forces on the curved part and the plane part of the tube in vertical position will be

A

π(a+b)4b\frac { \pi ( a + b ) } { 4 b }

B

2πab\frac { 2 \pi a } { b }

C

πa4b\frac { \pi a } { 4 b }

D

π(ab)4b\frac { \pi ( a - b ) } { 4 b }

Answer

π(a+b)4b\frac { \pi ( a + b ) } { 4 b }

Explanation

Solution

From the figure Curved part = semi perimeter =π(a+b)2= \frac { \pi ( a + b ) } { 2 }

and the plane part = minor axis = 2b

∴ Force on curved part = T×π(a+b)2T \times \frac { \pi ( a + b ) } { 2 }

and force on plane part = T×2bT \times 2 b

∴ Ratio =π(a+b)4b= \frac { \pi ( a + b ) } { 4 b }