Question

A linear harmonic oscillator of force constant $2 \times 10^6$ N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Show that its (a) maximum potential energy is 160 J (b) maximum kinetic energy is 100J

• A. P.E. is 160 J
• B. P.E. is zero
• C. P.E. is 100 J
• D. P.E. is 120 J

Answer 1

Answer: (C)

P.E. is 100 J

Answer 2

Force constant (k) = $2 \times 10^6$ N/m ; amplitude
(x) = 0.01 m and total mechanical energy = 160 J.
Potential energy = $\frac{1}{2} k \, x^2 = \frac{1}{2} \times ( 2 \times 10^6 ) \times (0. 0 1)^2$ = 100 J.