Question

A line through the point $A(2, 0)$ which makes an angle of $30^{\circ}$ with the positive direction of $x$-axis is rotated about $A$ in clockwise direction through an angle $15^{\circ}$. Then, the equation of the straight line in the new position is

• A. $\left(2-\sqrt{3}\right)x+y-4+2\sqrt{3}=0$
• B. $\left(2-\sqrt{3}\right)x-y-4+2\sqrt{3}=0$
• C. $\left(2-\sqrt{3}\right)x-y+4+2\sqrt{3}=0$
• D. $\left(2-\sqrt{3}\right)x+y+4+2\sqrt{3}=0$

Answer 1

Answer: (B)

$\left(2-\sqrt{3}\right)x-y-4+2\sqrt{3}=0$

Answer 2

The equation of line in new position is