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Question: A line segment of length (a + b) moves in such a way that its ends are always on two fixed perpendic...

A line segment of length (a + b) moves in such a way that its ends are always on two fixed perpendicular straight lines. Then the locus of the point on this line which divide it into portions of lengths a and b is-

A

A parabola

B

A circle

C

An ellipse

D

None of these

Answer

An ellipse

Explanation

Solution

a2 + b2 = (a + b)2

h = bαa+b\frac{b\alpha}{a + b} Ž a = h(a+b)b\frac{h(a + b)}{b}

k = aβa+b\frac{a\beta}{a + b} Ž b = k(a+b)a\frac{k(a + b)}{a}

h2(a+b)2b2\frac{h^{2}(a + b)^{2}}{b^{2}} + k2(a+b)2a2\frac{k^{2}(a + b)^{2}}{a^{2}} = (a + b)2

locus of (h, k) is

x2b2\frac{x^{2}}{b^{2}} + y2a2\frac{y^{2}}{a^{2}} = 1, ellipse