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Question: A line perpendicular to the line \(a x + b y + c = 0\) and passes through \(( a , b )\) The equation...

A line perpendicular to the line ax+by+c=0a x + b y + c = 0 and passes through (a,b)( a , b ) The equation of the line is.

A

bxay+(a2b2)=0b x - a y + \left( a ^ { 2 } - b ^ { 2 } \right) = 0

B

bxay(a2b2)=0b x - a y - \left( a ^ { 2 } - b ^ { 2 } \right) = 0

C

bxay=0b x - a y = 0

D

None of these

Answer

bxay=0b x - a y = 0

Explanation

Solution

The required equation of line which passes through (a,b) and gradient ba\frac { b } { a } is, yb=ba(xa)y - b = \frac { b } { a } ( x - a ) bxay=0\Rightarrow b x - a y = 0.