Question

A line passes through the point of intersection of $2 x + y = 5$ and $x + 3 y + 8 = 0$ and parallel to the line $3 x + 4 y = 7$ is.

• A. $3 x + 4 y + 3 = 0$
• B. $3 x + 4 y = 0$
• C. $4 x - 3 y + 3 = 0$
• D. $4 x - 3 y = 3$

Answer 1

Answer: (A)

$3 x + 4 y + 3 = 0$

Answer 2

Point of intersection $y = - \frac { 21 } { 5 }$ and $x = \frac { 23 } { 5 }$

$\therefore$ $3 x + 4 y = \frac { 3 ( 23 ) + 4 ( - 21 ) } { 5 } = \frac { 69 - 84 } { 5 } = - 3$ .

Hence, required line is $3 x + 4 y + 3 = 0$ .