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Question: A line passes through (2, 2) and is perpendicular to the line \(3x + y = 3\). Its *y*-intercept is...

A line passes through (2, 2) and is perpendicular to the line 3x+y=33x + y = 3. Its y-intercept is

A

13\frac{1}{3}

B

23\frac{2}{3}

C

1

D

43\frac{4}{3}

Answer

43\frac{4}{3}

Explanation

Solution

The equation of a line passing through (2, 2) and

perpendicular to 3x+y=33x + y = 3 is

y2=13(x2)y - 2 = \frac{1}{3}(x - 2) or x3y+4=0x - 3y + 4 = 0. Putting x=0x = 0 in this

equation, we obtain y=43y = \frac{4}{3}.

So y-intercept = 43\frac{4}{3}.