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Question: A line meets the coordinate axis in A and B. A circle is circumscribed about the triangle OAB. If ...

A line meets the coordinate axis in A and B.
A circle is circumscribed about the triangle OAB. If the distances from A and B of the tangent to the circle at the origin be m and n then the diameter of the circle is –

A

m (m + n)

B

m + n

C

n (m + n)

D

m2 + n2

Answer

m + n

Explanation

Solution

Coordinates of A be (a, 0) and B (0, b). AOB is right angled triangle centre of the circumscribed circle is mid point (a2,b2)\left( \frac{a}{2},\frac{b}{2} \right) of AB

and radius OC = a24+b24\sqrt{\frac{a^{2}}{4} + \frac{b^{2}}{4}}

equation of circle = x2 + y2 – ax – by = 0

AL and BM be the perpendicular from A and B on tangent at origin ax + by = 0

AL = a2a2+b2\left| \frac{a^{2}}{\sqrt{a^{2} + b^{2}}} \right| = m , BM = b2a2+b2\left| \frac{b^{2}}{\sqrt{a^{2} + b^{2}}} \right| = n

m + n = a2+b2\sqrt{a^{2} + b^{2}} = diameter of the circle.