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Question

Mathematics Question on Parallel Lines

A line l intersects the sides PQ and PR of a \triangle PQR at L and M respectively such that LM || QR. If PL = 5·7 cm, PQ = 15·2 cm and MR = 5·5 cm, then the length of PM (in cm) is :

A

3

B

1.8

C

2.5

D

3.3

Answer

3.3

Explanation

Solution

Using the basic proportionality theorem (LMQRLM \parallel QR):
PLPQ=PMPR\frac{PL}{PQ} = \frac{PM}{PR}
Substitute the known values:
5.715.2=PM5.7+5.5\frac{5.7}{15.2} = \frac{PM}{5.7 + 5.5}
5.715.2=PM11.2\frac{5.7}{15.2} = \frac{PM}{11.2}
Solve for PMPM:
PM=5.7×11.215.2=4.2cmPM = \frac{5.7 \times 11.2}{15.2} = 4.2 \, cm