Question

A line joining the points (1, 2, 0) and (4, 13, 5) is perpendicular to a plane. Then the coefficients of x, y and z in the equation of the plane are respectively

• A. 5, 15, 5
• B. 3, 11, 5
• C. 3, –11, 5
• D. – 5, – 15, 5

Answer 1

Answer: (B)

3, 11, 5

Answer 2

Since d.r's of line is also the d.r's of normal to the plane,

$\therefore$ Required coefficient of $x , y$ and z will be

$( 4 - 1 ) , ( 13 - 2 ) , ( 5 - 0 )$ i.e., $( 3,11,5 )$ .