Question
Question: A line bisecting the ordinate PN of a point P (at2, 2at), t \> 0, on the parabola y2 = 4ax is drawn ...
A line bisecting the ordinate PN of a point P (at2, 2at), t > 0, on the parabola y2 = 4ax is drawn parallel to the axis to meet the curve at Q. If NQ meets the tangent at the vertex at the point T, Then the coordinates of T are.
A
(0, (4/3) at)
B
(0, 2at)
C
(1/4) at2, at)
D
(0, at)
Answer
(0, (4/3) at)
Explanation
Solution
Equation of line TQ: y = at
Find Q point, Q : (4at2,at)N : (at2, 0)
To find T point solve the line NQ with y- axis.