Question

A line 4x + y = 1 through A(2, – 7) meets a line BC,

3x– 4y + 1 = 0 at B and AB = AC. Slope of the line AC is –

• A. – $\frac { 47 } { 81 }$
• B. – $\frac { 53 } { 91 }$
• C. – $\frac { 52 } { 89 }$
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

Suppose slope of AC is m.

Now, AB = AC

̃ ĐB = ĐC ̃ tan B = tanC

̃ $\left| \frac { m + 4 / 3 } { 1 - 4 m / 3 } \right|$ = $\left| \frac { ( - 4 ) + 4 / 3 } { 1 + ( - 4 ) ( - 4 / 3 ) } \right|$

̃ m = – 4 (rejected, because of slope of AB.) or – 52/89